may project po kami about ATM sa aming programming sa VB6....
dba dapat po may deposit sa ATM as of now may withdraw n kami at fast cash.......ngayon may isang prob po kami ung deposit ayaw nya po mag add sa fixed cash ng ATM nmin so ganito ung amking code....
dim a as integer
dim b as integer
b = 10000
a = b - val(nung sa withdraw) - val(nung sa fast cash)
lbloitput 1 = a

si lbloutput1 po ung label kung san andun ung 10000.....
pag gnawa ko po sya n

a = b - val(withdraw) - val(fastcash) + (deposit)

d po sya nag a-add sa 10000 pag gnamit ko po ung deposit bkt po kaya?:help::help::pray:
anu po kaya problema ko po dun.....

full details naman sa ginamit mong objects.. like what is withdraw. object ba siya (textbox) or static value. or better yet, rar mo yung may problem na project mo then attach it here on the thread and I'll try to help you with that. Ok. :thumbsup:

ok n poh ung akn ngawa ko n poh...tnx a lot n dn ......nxt time n lng poh...

ok na pu ba? pki closed na lng pu tong thread na to. pra wala na mgpopost.

hehe. bkt aQ? ng post dn.

anyway. pki close na lng pu.