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| Programming Discussions related to C++, HTML, PHP, ASP, ColdFusion, JavaScript, Perl, Phyton, Ruby, WML, SQL, XML, and other programming languages. |
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15th Mar 2012 Thu, 23:25
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The Grand Master
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Join Date: Feb 2012
Location: sa damit ko
Posts: 4,153
Reputation: 
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paano i-fix ang problem sa jump sa assembly language?
I have a problem to this program. Nag-eeror kasi ang mga jump niya. Sa mga nakakaalam po nito kong paano i-fix, help naman po..ASAP...
eTO po yong program..
Quote:
.model large
.stack 10h
.data
promp db "Press any no.$"
num db (?),'$'
excluded db "Out of range!$"
choose db "Select i/d:$"
one db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 39 dup(32),1,10,13
db 39 dup(32),1,10,13
db 39 dup(32),1,10,13
db 39 dup(32),1,10,13
db 39 dup(32),1,'$'
two db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 37 dup(32),4 dup(1),10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,10,13
db 37 dup(32),4 dup(1),10,13
db 37 dup(32),1,10,13
db 37 dup(32),1,10,13
db 37 dup(32),4 dup(1),'$'
three db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 37 dup(32),4 dup(1),10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,10,13
db 37 dup(32),4 dup(1),10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,10,13
db 37 dup(32),4 dup(1),'$'
four db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),4 dup(1),10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,'$'
five db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 37 dup(32),4 dup (1),10,13
db 37 dup(32),1,10,13
db 37 dup(32),1,10,13
db 37 dup(32),4 dup(1),10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,10,13
db 37 dup(32),4 dup(1),'$'
six db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),1,10,13
db 37 dup(32),1,10,13
db 37 dup(32),4 dup(1),10,13
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),4 dup(1),'$'
seven db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 37 dup(32),1,4 dup (32),1,10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,10,13,'$'
eight db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),4 dup(1),10,13
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),4 dup(1),'$'
nine db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 80 DUP(32)
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),1,4 dup (32),1,10,13
db 37 dup(32),4 dup(1),10,13
db 41 dup(32),1,10,13
db 41 dup(32),1,10,13
db 37 dup(32),4 dup(1),'$'
.code
mov ax,@data
mov dx,ax
mov ah,9
lea dx,promp
int 21h
mov ah,7
int 21h
mov num,al
cmp al,1
je usa
cmp al,2
je roha
cmp al,3
je tatlo
cmp al,4
je apat
cmp al,5
je lima
cmp al,6
je anom
cmp al,7
je pito
cmp al,8
je wayo
cmp al,9
je sidam
usa:
mov ax,3
int 10h
mov ah,9
lea dx,one
int 21h
roha:
mov ax,3
int 10h
mov ah,9
lea dx,two
int 21h
tatlo:
mov ax,3
int 10h
mov ah,9
lea dx,three
int 21h
apat:
mov ax,3
int 10h
mov ah,9
lea dx,four
int 21h
lima:
mov ax,3
int 10h
mov ah,9
lea dx,five
int 21h
anom:
mov ax,3
int 10h
mov ah,9
lea dx,six
int 21h
pito:
mov ax,3
int 10h
mov ah,9
lea dx,seven
int 21h
wayo:
mov ax,3
int 10h
mov ah,9
lea dx,eight
int 21h
sidam:
mov ax,3
int 10h
mov ah,9
lea dx,nine
int 21h
mov ah,9
lea dx,choose
int 21h
mov ah,7
int 21h
cmp al,'i'
je increment
cmp al,'d'
je decrement
cmp al,27
je exit
increment:
cmp num,1
je roha
cmp num,2
je tatlo
cmp num,3
je apat
cmp num,4
je lima
cmp num,5
je anom
cmp num,6
je pito
cmp num,7
je wayo
cmp num,8
je sidam
cmp num,9
mov ah,9
lea dx,excluded
int 21h
decrement:
cmp num,1
mov ah,9
lea dx,excluded
int 21h
cmp num,2
je usa
cmp num,3
je roha
cmp num,4
je tatlo
cmp num,5
je apat
cmp num,6
je lima
cmp num,7
je anom
cmp num,8
je pito
cmp num,9
je wayo
exit:
mov ah,4ch
int 21h
end
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Salamat po sa mga gustong makatulong... 
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16th Mar 2012 Fri, 08:24
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Forum Consultant
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Join Date: Oct 2007
Location: casa
Posts: 1,214
Reputation: 
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Re: paano i-fix ang problem sa jump sa assembly language?
hex gamitin mo or binary sa cmp 
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16th Mar 2012 Fri, 10:17
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Forum Advisor
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Join Date: May 2009
Posts: 710
Reputation: 
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Re: paano i-fix ang problem sa jump sa assembly language?
ano po bang error? 64bit kasi ako, di ko matry code mo. ang naencounter ko lang naman na error dati sa JUMP ay kapag masyado malayong lines na yung ijujump nya, ang ginawa ko, dalawang jump, parang me terminal pa.
TS tinry ko code mo sa emu8086, etong line lang ang error,
num db (?),'$'
dapat after ng num db, kung string, dapat nakaqoute, "" o kaya '', pero kung number, kahit hindi na, hal yung '$', pwedeng 36 un
Two Words, One Finger. 
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21st Mar 2012 Wed, 17:29
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The Grand Master
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Join Date: Feb 2012
Location: sa damit ko
Posts: 4,153
Reputation:
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Re: paano i-fix ang problem sa jump sa assembly language?
Quote:
Originally Posted by genius_am14
hex gamitin mo or binary sa cmp |
decimal lang po para wala na pahirap...
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21st Mar 2012 Wed, 17:38
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The Grand Master
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Join Date: Feb 2012
Location: sa damit ko
Posts: 4,153
Reputation:
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Re: paano i-fix ang problem sa jump sa assembly language?
Quote:
Originally Posted by Poldo
ano po bang error? 64bit kasi ako, di ko matry code mo. ang naencounter ko lang naman na error dati sa JUMP ay kapag masyado malayong lines na yung ijujump nya, ang ginawa ko, dalawang jump, parang me terminal pa.
TS tinry ko code mo sa emu8086, etong line lang ang error,
num db (?),'$'
dapat after ng num db, kung string, dapat nakaqoute, "" o kaya '', pero kung number, kahit hindi na, hal yung '$', pwedeng 36 un
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thanks po sa pagkakaroon ng interest...as of now po mejo nagawa ko na yang project na yan kaya nga lang..1 digit lang dapat 2 digit..
sa mga interested din po at gusto ako tulungan... try nyo tong code ko at help nyo ako i-edit pa po hanggang makuha yong desired output talaga na 2 digit ang i-iincrement and decrement sa display..
eto po code ko yong sa 1 digit:
Quote:
TITLE final project
.MODEL large
.STACK 50H
.DATA?
promp db "Enter a number only$"
FIR DB (?),'$'
TTL DB " IT-225 COMPUTER ORGANIZATION WITH ASSEMBLY LANGUAGE", 10, 13
DB " FINAL PROJECT $"
DIS DB 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 80 DUP(32), '$'
PMT DB "please select i/d/ESC:$"
EXCLUDED DB "You have been reach the limit..$"
MSG DB " BY BSIT 2/BLK.1", 10, 13
DB " TO ENGR.RICHARD D. GARCIA,M.I.T $"
.CODE
MOV AX, @DATA
MOV DS, AX
START:
;CLEAR_SCREEN
MOV AX, 3
INT 10H
;TITLE_MESSAGE
MOV AH, 9
LEA DX, TTL
INT 21H
;CREDIT_MESSAGE
MOV AH, 02H
MOV BH, 00H
MOV DH, 16H
MOV DL, 00H
INT 10H
MOV AH, 9
LEA DX, MSG
INT 21H
;BLACK_TEXT
MOV AX, 0607H
MOV BX, 0000H
MOV CX, 0541H
MOV DX, 000DH
INT 10H
;MATRIX_DISPLAY
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
mov ah,9
lea dx,promp
int 21h
FIR_INDEX0:
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 7
INT 21H
FIR_SKIP:
CMP AL, 30H
JB FIR_INDEX0
CMP AL, 39H
JA FIR_INDEX0
MOV FIR, AL
SUB FIR, 30H
mov BL,AL
INCR:
SEG_1_1:
CMP FIR, 1
JE SEG_1_2
CMP FIR, 4
JE SEG_1_2
MOV AX, 0601H ;top
MOV BX, 0C00H
MOV CX, 0511H
MOV DX, 000DH
INT 10H
SEG_1_2:
CMP FIR, 1
JE SEG_1_3
CMP FIR, 7
JE SEG_1_3
MOV AX, 0601H
MOV BX, 0C00H
MOV CX, 0811H;mid
MOV DX, 000DH
INT 10H
SEG_1_3:
CMP FIR, 1
JE SEG_1_4
CMP FIR, 4
JE SEG_1_4
CMP FIR, 7
JE SEG_1_4
MOV AX, 0601H
MOV BX, 0C00H;bottom
MOV CX, 0B11H
MOV DX, 000DH
INT 10H
SEG_1_4:
CMP FIR, 1
JE SEG_1_5
CMP FIR, 2
JE SEG_1_5
CMP FIR, 3
JE SEG_1_5
CMP FIR, 7
JE SEG_1_5
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 050aH;ul
MOV DX, 000DH
INT 10H
SEG_1_5:
CMP FIR, 5
JE SEG_1_6
CMP FIR, 6
JE SEG_1_6
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 0511H;ur
MOV DX, 0011H
INT 10H
SEG_1_6:
CMP FIR, 1
JE SEG_1_7
CMP FIR, 3
JE SEG_1_7
CMP FIR, 4
JE SEG_1_7
CMP FIR, 5
JE SEG_1_7
CMP FIR, 7
JE SEG_1_7
CMP FIR, 9
JE SEG_1_7
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 080DH;ll
MOV DX, 000DH
INT 10H
SEG_1_7:
CMP FIR, 2
JE FIR_DISPLAY_1
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 0811H;lr
MOV DX, 0011H
INT 10H
FIR_DISPLAY_1:
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
back:
mov ah,9
lea dx,PMT
INT 21H
cur:
MOV AH,7
INT 21H
cmp al,27
je exit
cmp al,'i'
je increment
cmp al,'d'
je decrement
jne cur
increment:
inc FIR
cmp FIR,10
JE TIGIL
MOV AX, 3
INT 10H
;BLACK_TEXT
MOV AX, 0607H
MOV BX, 0000H
MOV CX, 0541H
MOV DX, 000DH
INT 10H
; MATRIX_DISPLAY
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
JMP INCR
decrement:
DEC FIR
cmp FIR,0
JE TIGIL
MOV AX, 3
INT 10H
;BLACK_TEXT
MOV AX, 0607H
MOV BX, 0000H
MOV CX, 0541H
MOV DX, 000DH
INT 10H
;MATRIX_DISPLAY
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
JMP INCR
TIGIL:
mov ah,2
mov dl,10
int 21h
mov dl,13
int 21h
MOV AH,9
LEA DX,EXCLUDED
INT 21H
EXIT:
MOV AH,4CH
INT 21H
END
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at eto naman po yong nasimulan ko na para sa 2 digit,mejo gumagana na yan..kaso malayo pa talaga sa katotohanan...sensya po kayo mahaba talaga...
eto po siya:
Quote:
TITLE final project
.MODEL large
.STACK 50H
.DATA?
promp db "Enter a number only$"
SEC DB 2 DUP (?)
TTL DB " IT-225 COMPUTER ORGANIZATION WITH ASSEMBLY LANGUAGE", 10, 13
DB " FINAL PROJECT $"
DIS DB 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 13 DUP(32), 30 DUP (219), 10, 13
DB 80 DUP(32), '$'
PMT DB "please select i/d/ESC:$"
EXCLUDED DB "You have been reach the limit..$"
MSG DB " BY BSIT 2/BLK.1", 10, 13
DB " TO ENGR.RICHARD D. GARCIA,M.I.T $"
.CODE
MOV AX, @DATA
MOV DS, AX
START:
;CLEAR_SCREEN
MOV AX, 3
INT 10H
;TITLE_MESSAGE
MOV AH, 9
LEA DX, TTL
INT 21H
;CREDIT_MESSAGE
MOV AH, 02H
MOV BH, 00H
MOV DH, 16H
MOV DL, 00H
INT 10H
MOV AH, 9
LEA DX, MSG
INT 21H
;BLACK_TEXT
MOV AX, 0607H
MOV BX, 0000H
MOV CX, 0541H
MOV DX, 000DH
INT 10H
;MATRIX_DISPLAY
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
FIR_DISPLAY_2:
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
SEC_INDEX0:
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 1FH
INT 10H
MOV AH, 7
INT 21H
CMP AL, 31H
JB SEC_INDEX0
CMP AL, 39H
JA SEC_INDEX0
MOV SEC[0], AL
SUB SEC[0], 30H
INCR:
SEG_3_1:
CMP SEC[0], 1
JE SEG_3_2
CMP SEC[0], 4
JE SEG_3_2
MOV AX, 0601H
MOV BX, 0C00H
MOV CX, 0523H
MOV DX, 001FH
INT 10H
SEG_3_2:
CMP SEC[0], 1
JE SEG_3_3
CMP SEC[0], 7
JE SEG_3_3
MOV AX, 0601H
MOV BX, 0C00H
MOV CX, 0823H
MOV DX, 001FH
INT 10H
SEG_3_3:
CMP SEC[0], 1
JE SEG_3_4
CMP SEC[0], 4
JE SEG_3_4
CMP SEC[0], 7
JE SEG_3_4
MOV AX, 0601H
MOV BX, 0C00H
MOV CX, 0B23H
MOV DX, 001FH
INT 10H
SEG_3_4:
CMP SEC[0], 1
JE SEG_3_5
CMP SEC[0], 2
JE SEG_3_5
CMP SEC[0], 3
JE SEG_3_5
CMP SEC[0], 7
JE SEG_3_5
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 051FH
MOV DX, 001FH
INT 10H
SEG_3_5:
CMP SEC[0], 5
JE SEG_3_6
CMP SEC[0], 6
JE SEG_3_6
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 0523H
MOV DX, 0023H
INT 10H
SEG_3_6:
CMP SEC[0], 1
JE SEG_3_7
CMP SEC[0], 3
JE SEG_3_7
CMP SEC[0], 4
JE SEG_3_7
CMP SEC[0], 5
JE SEG_3_7
CMP SEC[0], 7
JE SEG_3_7
CMP SEC[0], 9
JE SEG_3_7
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 081FH
MOV DX, 001FH
INT 10H
SEG_3_7:
CMP SEC[0], 2
JE SEC_DISPLAY_1
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 0823H
MOV DX, 0023H
INT 10H
SEC_DISPLAY_1:
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
SEC_INDEX1:
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 25H
INT 10H
MOV AH, 7
INT 21H
CMP AL, 13
JNE SEC_SKIP
MOV BL, SEC[0]
MOV SEC[1], BL
MOV SEC[0], 0
jmp BACK
SEC_SKIP:
CMP AL, 30H
JB SEC_INDEX1
CMP AL, 39H
JA SEC_INDEX1
MOV SEC[1], AL
SUB SEC[1], 30H
INCR1:
SEG_4_1:
CMP SEC[1], 1
JE SEG_4_2
CMP SEC[1], 4
JE SEG_4_2
MOV AX, 0601H
MOV BX, 0C00H
MOV CX, 0529H
MOV DX, 0025H
INT 10H
SEG_4_2:
CMP SEC[1], 0
JE SEG_4_3
CMP SEC[1], 1
JE SEG_4_3
CMP SEC[1], 7
JE SEG_4_3
MOV AX, 0601H
MOV BX, 0C00H
MOV CX, 0829H
MOV DX, 0025H
INT 10H
SEG_4_3:
CMP SEC[1], 1
JE SEG_4_4
CMP SEC[1], 4
JE SEG_4_4
CMP SEC[1], 7
JE SEG_4_4
MOV AX, 0601H
MOV BX, 0C00H
MOV CX, 0B29H
MOV DX, 0025H
INT 10H
SEG_4_4:
CMP SEC[1], 1
JE SEG_4_5
CMP SEC[1], 2
JE SEG_4_5
CMP SEC[1], 3
JE SEG_4_5
CMP SEC[1], 7
JE SEG_4_5
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 0525H
MOV DX, 0025H
INT 10H
SEG_4_5:
CMP SEC[1], 5
JE SEG_4_6
CMP SEC[1], 6
JE SEG_4_6
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 0529H
MOV DX, 0029H
INT 10H
SEG_4_6:
CMP SEC[1], 1
JE SEG_4_7
CMP SEC[1], 3
JE SEG_4_7
CMP SEC[1], 4
JE SEG_4_7
CMP SEC[1], 5
JE SEG_4_7
CMP SEC[1], 7
JE SEG_4_7
CMP SEC[1], 9
JE SEG_4_7
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 0825H
MOV DX, 0025H
INT 10H
SEG_4_7:
CMP SEC[1], 2
JE SEC_DISPLAY_2
MOV AX, 0604H
MOV BX, 0C00H
MOV CX, 0829H
MOV DX, 0029H
INT 10H
SEC_DISPLAY_2:
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
back:
mov ah,9
lea dx,PMT
INT 21H
cur:
MOV AH,7
INT 21H
cmp al,27
je quit
cmp al,'i'
je increment
cmp al,'d'
je gets
jne cur
gets:
jmp decrement
quit:
jmp exit
increment:
inc SEC[1]
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
JMP INCR1
cmp SEC[1],9
JE DAGDAG
DAGDAG:
MOV SEC[1],0
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
JMP INCR1
ADD SEC[0],1
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
JMP INCR
loop increment
decrement:
DEC SEC[1]
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
JMP INCR1
CMP SEC[1],0
JE BAWAS
BAWAS:
MOV SEC[1],9
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
JMP INCR1
SUB SEC[0],1
MOV AH, 02H
MOV BH, 00H
MOV DH, 05H
MOV DL, 0DH
INT 10H
MOV AH, 9
LEA DX, DIS
INT 21H
JMP INCR
loop decrement
exit:
MOV AH,4CH
INT 21H
END
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kung masolve nyo po agad mas maganda po kasi bukas na deadlinne ng project namin na yan...thanks po sa lahat ng interesado na makatulong...  
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15th Jul 2012 Sun, 13:52
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The Grand Master
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Join Date: Feb 2012
Location: sa damit ko
Posts: 4,153
Reputation:
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Re: paano i-fix ang problem sa jump sa assembly language?
gandang hapon sa lahat...
pasok kayo dito.... 
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