Pa-tulong naman po: About PHP

[hardcorekid03]

Hi, newbie po ako sa php, tanong ko lang po sana kung pano kunin yung value ng textbox para gawing filename nung i-uupload kong image sa directory. ito po ang codes ko

<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
$check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
if($check !== false) {
echo "File is an image - " . $check["mime"] . ".";
$uploadOk = 1;
} else {
echo "File is not an image.";
$uploadOk = 0;
}
}
// Check if file already exists
if (file_exists($target_file)) {
echo "Sorry, file already exists.";
$uploadOk = 0;
}
// Check file size
if ($_FILES["fileToUpload"]["size"] > 500000) {
echo "Sorry, your file is too large.";
$uploadOk = 0;
}
// Allow certain file formats
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
$uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";
} else {
echo "Sorry, there was an error uploading your file.";
}
}


?>
​

salamat po sa tutulong

 

[jskhulitz]

assuming na meron ka maayos na form na meron textbox - <input type="text" name="imageName">

upon form submission, dalawang data array ang maipapasa jan, yung $_FILES - nandito yung lahat ng data na may kinalaman sa file na ia-upload mo, tsaka $_POST - nandito naman ung ibang laman ng form mo, dito sasama ung textbox value.

Nakikita mo ito?

if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file))

Yan ang function na maga-upload / mag-transfer ng file mo papunta sa server directory, ang syntax nyan ay

move_uploaded_file(<file to be uploaded>, <upload directory and new filename>)

ung 1st parameter ng function na yan ay manggagaling sa $_FILES array mo - $_FILES["fileToUpload"]["tmp_name"].
ung 2nd parameter ay manggagaling yan sa kung ano ang ii-specify mo,

$temp = explode(".", $_FILES["file"]["name"]); // kailangan ito para "ma-extract ung file extension ng file. ang magiging value ng $temp ay jpg, bmp, xls, xlsx r kung ano mang file extension
$target_file = $target_dir . $_POST['imageName'] . '.' . end($temp); // kinuha lang dito ung last part ng exploded array, kasi un ung may hawak sa extension name, tapos ikakabit natin sa filename na ipapalit natin sa original, ia-assign uli ito sa $target_file

#tapos dadaan sa standard checking kung yung new filename ay existing sa upload directory, para maiwasan ang file duplication
if (file_exists($target_file)) {
echo "Sorry, file already exists.";
$uploadOk = 0;
}

#proceed with your current code

 

[hardcorekid03]

assuming na meron ka maayos na form na meron textbox - <input type="text" name="imageName">

upon form submission, dalawang data array ang maipapasa jan, yung $_FILES - nandito yung lahat ng data na may kinalaman sa file na ia-upload mo, tsaka $_POST - nandito naman ung ibang laman ng form mo, dito sasama ung textbox value.

Nakikita mo ito?

if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file))

Yan ang function na maga-upload / mag-transfer ng file mo papunta sa server directory, ang syntax nyan ay

move_uploaded_file(<file to be uploaded>, <upload directory and new filename>)

ung 1st parameter ng function na yan ay manggagaling sa $_FILES array mo - $_FILES["fileToUpload"]["tmp_name"].
ung 2nd parameter ay manggagaling yan sa kung ano ang ii-specify mo,

$temp = explode(".", $_FILES["file"]["name"]); // kailangan ito para "ma-extract ung file extension ng file. ang magiging value ng $temp ay jpg, bmp, xls, xlsx r kung ano mang file extension
$target_file = $target_dir . $_POST['imageName'] . '.' . end($temp); // kinuha lang dito ung last part ng exploded array, kasi un ung may hawak sa extension name, tapos ikakabit natin sa filename na ipapalit natin sa original, ia-assign uli ito sa $target_file

#tapos dadaan sa standard checking kung yung new filename ay existing sa upload directory, para maiwasan ang file duplication
if (file_exists($target_file)) {
echo "Sorry, file already exists.";
$uploadOk = 0;
}

#proceed with your current code

thanks sir, nagawa ko na po, maraming salamat ito yung naging code ko

$target_dir = "uploads/";
$file_parts = explode('.', $_FILES["fileToUpload"]["name"]);
$ext = $file_parts[count($file_parts) - 1];
$target_file = $target_dir . $_POST['tin']. '-'.$_POST['ftype']. '-'. $_POST['fmonth']. '.' . $ext;
$uploadOk = 1;$file_parts = explode('.', $_FILES["fileToUpload"]["name"]);
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);