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Official Tambayan ng Electronics Engineers
- Thread starter charls mada
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ok sige sirs try ko.
yan. Online pala ako everyday except thursdays from 6pm - 10:30 pm kung may mga tanong kayo.
may 3V na battery. kaso dalawang 1.5V yun na naka series connection.
btw, eto yung tinry namin sa breadboard sa school.. kaso wala kaming 3V na battery kaya hindi namin alam kung nagana ba talaga or hindi..
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yung 24 second shot clock po ay count down starting from 24 at magstop sya sa 00...
dual 7-segement po yung gamit namin...
may 2 push button switches po..yung isa pang pause at resume tapos yung isa pa ay pang reset...kapag hinold po yung reset switch, nakadisplay lang ang "24" tapos pag nirelease ay start ulit sya ng count down...
dual 7-segement po yung gamit namin...
may 2 push button switches po..yung isa pang pause at resume tapos yung isa pa ay pang reset...kapag hinold po yung reset switch, nakadisplay lang ang "24" tapos pag nirelease ay start ulit sya ng count down...
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sige po sirs try ko baka bukas. dami pako gawin ngayun eh.
Paki sunod yung nakatype sa box. The rest, ok na yung connection. tapos, try mo muna gumamit ng 1.5V na battery. Pag gumana, e di ayos! kung hinde, dun ka lang magdagdag ng isa pang battery para maging 3V
summation of forces along X = Rx (1)Patulong po about sa Engineering Mechanics. Nasa Force System po kami na topic. Heto ang Problem:
Find the resultant forces that acts on the truss shown. Also find where its intersect line in point CB.
summation of forces along Y = Ry (2)
summation of torque at point B = 0 (3)
summation of torque at point A = 0 (4)
summation of torque at point E = 0 (5)
R = sqrt(Rx^2 + Ry^2) (6)
theta = arctan (Ry / Rx) (7)
Kung di ako nagkakamali, dalawang force ang mag-act sa point B. I-assume mo na positive upward yung By at positive rightward yung Bx
(1): 240kN + Bx = Rx
(2): -400kN - 600kN + Ay + By = Ry
(3): 240kN(4m) - 400kN(9m) - 600kN(3m) + Ay(6m) = 0
(4): -400kN(3m) + 240kN(4m) + 600kN(3m) - By(6m) = 0
(5): -400kN(6m) + Ay(3m) - By(3m) - Bx(4m) = 0
Btw, hindi ako 100% sure dyan. yan yung naalala ko nung nag statics kami last S.Y. hahaha
consult mo rin yung notes mo at yung prof mo or yung ibang may alam para maka-sigurado ka.. yung 2nd question di ko alam kung ano ibig sabihin..
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Eto representation ng roller at ng pin. ang roller, y component lang ang meron since nasa point A siya, tawagin natin siyang Ay. Yung pin naman, may x and y component at since nasa point B siya, awagin natin yung components niya na Bx at By... at eto ang solution...
Moment! So familiar ka na sa moment na force x distance para makagawa ng moment di ba? so kunin natin yung values ng Ay, Bx at By gamit ang moment. ikaw na bahala mag analyze...
Gawin nating pivot ang point A para maeliminate ang Ay at Bx. Ang matitira yung By:
Summation of Moment @ A = 0 (Assuming clockwise rotation as positive)
0 = 4(240k) + 3(600k) - 3(400k) - 6(By)
By = 260k
Gawin nating pivot ang point B para maeliminate ang Bx at By. Ang matitira yung Ay:
Summation of Moment @ B = 0 (Assuming clockwise rotation as positive)
0 = 4(240k) - 3(600k) - 9(400k) + 6(Ay)
Ay = 740k
So ang matitira na lang ay yung Bx. Dalawa pwedeng solution: Summation of Forces along x axis at moment ulit. Trynatin muna moment:
Summation of Moment @ E = 0 (Assuming clockwise rotation as positive) para maeliminate yung 240k at 600k na force.
0 = 3(740k) -6(400k) -3(260k) -4(Bx)
Bx = 240k
so kung summation of forces naman:
Summation of forces at x axis = 0
0 = 240k (pointing right) - Bx (pointing left)
Bx (pointing left) = 240k
so pareho sila ng sagot.
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umilaw naaaaaaaa!! Salamaaaaaaaaaaatttttt!!! umilaw kahit 1.5V battery lang yung ginamit ko.. hahaha
paki sunod yung nakatype sa box. The rest, ok na yung connection. Tapos, try mo muna gumamit ng 1.5v na battery. Pag gumana, e di ayos! Kung hinde, dun ka lang magdagdag ng isa pang battery para maging 3v
btw, paano po ba pailawin yung LED light? kailangan po kasi naming patunayan na mas maliwanag siya kapag naka-kabit dun sa circuit compared sa hndi.. hehehe
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PAANO PO b papailawin yung LED lang mismo? ikakabit ko lang po ba sa battery tapos iilaw na? white LED po gamit namin..ahahaha! nice one! ang galing mo sir!
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battery tapos konek mo yung isang paa ng 1kohm resistor sa positive terminal ng batt tapos yung isang paa ng resistor sa anode (yung mahabang paa) tapos connect mo yung cathode (maikling paa) sa negative terminal ng battery.
Battery - Resistor - LED
Kasi current ang magpapailaw sa LED, hindi yung 1.5V.
Battery - Resistor - LED
Kasi current ang magpapailaw sa LED, hindi yung 1.5V.
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Patulong po about sa Engineering Mechanics. Nasa Force System po kami na topic. Heto ang Problem:
Find the resultant forces that acts on the truss shown. Also find where its intersect line in point CB.
Resultant of Force System pa po muna at di po Equilibrium. Pinagtawanan ako kasi napaka-advance ko daw po.
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hindi po ba pwedeng battery tapos LED agad?
umiilaw naman po yung LED kaso sa 9V battery.. hahaha
sa 1.5V ayaw umilaw..
tska sirs may e-book ka ba dyan para sa introductory circuits? yung may solutions manual? para makapag-praktis ako ng pagsosolve ng network theorems, resistance, capacitance, inductance, etc...
tska sirs baka may apps ka dyan na katulad ng Multisim, pero pang PCB naman.. para hindi na kami magkamali sa paghihinang. mahirap na eh.. mahal pa naman PCB..
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Help! Ano po pwdeng maging food for thoughts, ice breaker na pede iperform? Kelangan ko po kc bgo mgreport. Slamat.
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kulang kasi yung current na hinuhugot ng led kaya sa 9v lang siya umiilaw. resistor ang makakagawa nung paghugot ng current na yun kaya umilaw siya sa 1.5v di ba?
try mo hanapin yung program na PCB Wizard. yun, makikita mo kung paano gumawa ng pcb tapos sila na rin gagawa ng layout mo.
regarding sa ebooks, mas maganda kung si sir electrons tatanungin mo nun. di kasi ako nagrerely sa ebooks eh. may sarili akong reference, yung book mismo.
try mo hanapin yung program na PCB Wizard. yun, makikita mo kung paano gumawa ng pcb tapos sila na rin gagawa ng layout mo.
regarding sa ebooks, mas maganda kung si sir electrons tatanungin mo nun. di kasi ako nagrerely sa ebooks eh. may sarili akong reference, yung book mismo.
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Pasintabi po Sir, LED white super bright po ang gamit nila, LED super bright Blue and White needs 3V to 4V para magoperate, higher voltage ang kailangan ng mga LED na yan at hindi higher current, that is the function of the circuit, hindi pwedeng idirect ang LED super bright (white or blue) sa 1.5V na battery dahil hindi siya iilaw kahit 5A pa iyan...
Sa page 9 po ng thread na ito nagpost po ako ng inupload kong EAGLE, pang PCB designing po ang software na iyon,. Kayo na bahala kung ayaw niyong gamitin yun...
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red LED yung nakalagay sa breadboard nila.
ang voltage yung magdedetermine kung iilaw ung LED pero yung current ang magdedetermine ng intensity ng ilaw (kung gaano kabright). Kaya may makikita na graph ng forward current vs luminus intensity sa spec sheet ng LED.
ang voltage yung magdedetermine kung iilaw ung LED pero yung current ang magdedetermine ng intensity ng ilaw (kung gaano kabright). Kaya may makikita na graph ng forward current vs luminus intensity sa spec sheet ng LED.
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sirs, supposedly white talaga yun.. at white po talaga ang gagamitin namin. nagkataon lang na walang white sa Multisim na ginagamit namin,.. ehehe
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hindi sir transistor capacitor-coupled lang, Electronics 3, reference is David Bell thanks
