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Mechanical Engineering Thread
- Thread starter Jabaps
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Meron po ba dito may pdf ng mga following text books?
-Power Plant Engineering by Morse MKS
-Power Plant Theory and Design by Potter
-Any power and industrial plant books
Or baka po may alam kayong murang bilihan ng unang dalawang book sa manila
-Power Plant Engineering by Morse MKS
-Power Plant Theory and Design by Potter
-Any power and industrial plant books
Or baka po may alam kayong murang bilihan ng unang dalawang book sa manila
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Meron po ba dito may pdf ng mga following text books?
-Power Plant Engineering by Morse MKS
-Power Plant Theory and Design by Potter
-Any power and industrial plant books
Or baka po may alam kayong murang bilihan ng unang dalawang book sa manila
Meron sa torrent hanap ka lang ng maigi
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Mga bossing ilang tanong po kada subject sa board? student pa lang po ako hehe
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^ tatlong subject.. pipe, general math at machine design .. 100 items per subject .
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Mga kapwa ME dyan, okay po bang CADET ENGINEER ang applyan? May career ba dun? Salamat
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ka me pasagot naman
A closed rigid container has a volume of 1m^3 and holds air at 344.8 kpa and 273°k. heat is added until the temp. is 600°k. det. change in internal energy.salamas in advance.
A closed rigid container has a volume of 1m^3 and holds air at 344.8 kpa and 273°k. heat is added until the temp. is 600°k. det. change in internal energy.salamas in advance.
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Bro wala akong calcu ngayon eh, pero try mo to.
Keyword "closed rigid container" ----> constant volume siya. Alam natin na ang equation for internal energy is U = Q + Wn, but constant volume so Wn = 0
then, U = Q, ang Q = mCv(T2 - T1)
yung mass makukuha mo sa PV=mRT, gamitin mo yung point 1 para makuha si mass
tapos substitute mo nalang sa U = mCv(T2-T1).
Payo ko lang bro focus ka sa concept para sisiw magsolve. Kaya yan hehe mabuhay mga ME!
Keyword "closed rigid container" ----> constant volume siya. Alam natin na ang equation for internal energy is U = Q + Wn, but constant volume so Wn = 0
then, U = Q, ang Q = mCv(T2 - T1)
yung mass makukuha mo sa PV=mRT, gamitin mo yung point 1 para makuha si mass
tapos substitute mo nalang sa U = mCv(T2-T1).
Payo ko lang bro focus ka sa concept para sisiw magsolve. Kaya yan hehe mabuhay mga ME!
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choco tol thanks eto pa
20 li tank contains sat. liquid n sat. vapor at 200 ℃. if the mass of liquid is 5 kg, find the moisture content of steam.salamas in advancd
20 li tank contains sat. liquid n sat. vapor at 200 ℃. if the mass of liquid is 5 kg, find the moisture content of steam.salamas in advancd
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sir sa MEP po position niyo? patulong naman haha fresh grad kasi ako and ang hirap kapag walang exp sa cad.
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- convert 20 li to cubic meters
- get specific volume of liquid and vapor using steam table at 200 C, yan yung vf at vg take note sa steam table naka times 10 raise to -3 yon.
*sa temperature table ka titingin ah
- solve for the volume of liquid, Volume of liquid = (mass of liquid)(specific volume of liquid at 200 C)
- solve for the volume of vapor, V vapor = V total - V liquid
- solve for mass of vapor, mass of vapor = Volume of vapor / specific volume of vapor
- solve for total mass, mass total = mass of liquid + mass of vapor
- solve for moisture content, % moisture = (mass of liquid / total mass) x 100
pacheck nalang din sa mga master natin dyan hehe
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ka ME talo ba ko sa maintenance staff na position lang? how much ang salary? sabi nila magbabase daw s years of experiences 4 years n 3 months lang ako..pero abroad siya sa tingin nyo makatarungan ba un? thanks ka M.E.
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