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[ TUT ] MATH - CALCULATOR TECHNIQUEs

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  • Oo, malaking tulong..Natututo ako dito..More pa TS

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haha bat ganun idol calculator ko loading ung sagot amf antagal. XD thanks nga pala.
 
share ko lang din ng CALCU TECHNIQUE sa Laplace Transformation:



Examples:

1. Find the laplace transform of f(t) = cosh 5t
a. (5 / s^2 - 25)
b. (5s / s^2 - 25)
c. (s / s^2 + 25)
d. (s / s^2 - 25)


Steps: By calculator technique (FX991ES+):

Let t = x
a. Press the Integral sign sa calculator (yung nasa baba ng alpha button)
b. Type mo (e^-9x) (cosh 5x)
c. Then yung limit po, ilagay nyo po 0 to 9
d. Answer is .1607. Take note of the answer.

Para po malaman mo kung anu yung laplace transform nya sa choices, trial and error from the choices, just change "s" to 9. Like for this example, letter d yung may kaparehas na sagot.


2. Find the inverse laplace of [3(s^2-2)^2] / 2s^5
a. (3/2) + 3t^2 + (t^4/4)
b. (3/2) - 3t^2 - (t^4/4)
c. - (3/2) - 3t^2 + (t^4/4)
d. (3/2) - 3t^2 + (t^4/4)


Steps: By calculator technique (FX991ES+):

Let t = x & s = 9
a. From this example, reverse process po ang gagawin. Just input sa calculator yung inverse laplace equation. Ang sagot po dapat sa equation na [3(s^2-2)^2] / 2s^5 ay .158537
b. From the given choices, trial and error po uli ang gagawin. Sa question, letter "d" po yung sagot
c. Press the Integral sign sa calculator (yung nasa baba ng alpha button)
d. Type mo (e^-9x) ([3(s^2-2)^2] / 2s^5).
e. Limit is the same from 0 to 9, then press =. Medjo matagal nga lang po lumabas yung sagot.
f. Ang sagot po dapat ay .158537


Sana po nakatulong sa nyo kahit paano. Sana makapasa tayong lahat sa board exam. God Bless :)


"Knowledge are meant to be shared, not to be kept"
 
Last edited:
sir di ko magets yung #3 :noidea: panu yung CALCU function na sinasabi dun? naibasura ko na kasi yung manual ng akin
 
Ns po nid ko po to...nde po kc q maxado marunong sa pgm8 nyang calculator n yan...
 
robgab said:
share ko lang din ng CALCU TECHNIQUE sa Laplace Transformation:



Examples:

1. Find the laplace transform of f(t) = cosh 5t
a. (5 / s^2 - 25)
b. (5s / s^2 - 25)
c. (s / s^2 + 25)
d. (s / s^2 - 25)


By calcu technique (FX991ES+):

Let t = x
1. Press the Integral sign sa calcu
2. Type mo (e^-9x) (cosh 5x)
3. Then yung limit po, ilagay nyo po 0 to 9
4. Answer is .1607. Take note of the answer.

Para po malaman mo kung anu yung laplace transform nya sa choices, trial and error from the choices, just change "s" to 9. Like for this example, letter d yung may kaparehas na sagot.


2. Find the inverse laplace of [3(s^2-2)^2] / 2s^5
a. (3/2) + 3t^2 + (t^4/4)
b. (3/2) - 3t^2 - (t^4/4)
c. - (3/2) - 3t^2 + (t^4/4)
d. (3/2) - 3t^2 + (t^4/4)


By calcu technique (FX991ES+):

Let t = x & s = 9
1. From this example, reverse process po ang gagawin. Just input sa calcu yung inverse laplace equation. Ang sagot po dapat sa equation na [3(s^2-2)^2] / 2s^5 ay .158537
2. From the given choices, trial and error po uli ang gagawin. Sa question, letter "d" po yung sagot
3. Press the Integral sign sa calcu
4. Type mo (e^-9x) ([3(s^2-2)^2] / 2s^5).
5. Limit is the same from 0 to 9, then press =. Medjo matagal nga lang po lumabas yung sagot.
6. Ang sagot po dapat ay .158537


Sana po nakatulong sa nyo kahit paano. Sana makapasa tayong lahat sa board exam. God Bless :)


"Knowledge are meant to be shared, not to be kept"
Click to expand...

:thanks: I will add this to first page.

azean07 said:
sir di ko magets yung #3 :noidea: panu yung CALCU function na sinasabi dun? naibasura ko na kasi yung manual ng akin
Click to expand...

Ah, sorry for that. It's CALC not CALCU pero same lang din naman yun. Makikita mo yun sa upper left corner sa baba ng SHIFT.

blitzkriegz91 said:
may pasok po ba sa edge bukas??? aug 10,2012
Click to expand...

kiko800 said:
Ns po nid ko po to...nde po kc q maxado marunong sa pgm8 nyang calculator n yan...
Click to expand...

:welcome: more to come.
​
 
Session 2 Part 4


SESSION 2 PART 4​

31. A radioactive substance decreases from 10 grams to 9 grams in two hours. Find its half life.
A. 10.19 hr
B. 11.49 hr
C. 12.89 hr
D. 13. 16 hr

Code: 
Dahil sa ito ay radioactive, nagiincrease ito exponentially. Which means kung exponentially ito, gagamitin natin ang STAT 5..

Ang x column natin ay ang time(hr) and y column natin ay quantity..
X-----|-----Y
0-----|-----10
2-----|-----9

since time in its half life ang hinahanap, press AC then find [IMG]http://latex.codecogs.com/gif.latex?5\hat{x}[/IMG]

32. A thermometer reading
gif.latex
is brought into a room where the temperature is
gif.latex
; 1 min later, the thermometer reading is
gif.latex
. Find the temperature equation as a function of time.
A.
gif.latex

B.
gif.latex

C.
gif.latex

D.
gif.latex


Code: 
Pag temperature ang pinaguusapan use STAT 5.
Sa x column natin is the time(min) and in y column it's either "Ts-T" or "T-Ts" (temperature). It depends kung sino malaki kung si T or si Ts..
T = Object temperature
Ts = surrounding/environment temperature

gets?. Let's proceed..

Since malaki ang Ts natin which is [IMG]http://latex.codecogs.com/gif.latex?70^{\circ}F[/IMG], therefore ang gagamitin natin ay Ts-T. Gets?..

X-----|-----Y(Ts-T)
0-----|-----(70-18)
1-----|-----(70-31)

After natin ma-input ang data, press AC. Since ang kinukuha natin dito ay equation, therefore kukunin natin ang value ng A and B. I hope and assume na you know it already kung paano at saan ito kukunin since naturo ko na ito sa naunang session/part..

After makuha ang A and B, alam natin na ang equation sa STAT 5 ay [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20y=Ae^{bx}[/IMG]
I-substitute ang A and B, x=t and y=Ts-T since yun ang ginamit natin(y=70-T)

33. How fast does light travel in glass of refractive index 1.5?
A.
gif.latex

B.
gif.latex

C.
gif.latex

D.
gif.latex


Code: 
Refractive index formula [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20n=\frac{c(vacuum)}{v(medium)}[/IMG]

[IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%201.5=\frac{3x10^{8}}{v}[/IMG]

34. At the surface of the earth,
gif.latex
. Assume the earth to be a sphere of radius 6,371 km, compute the mass of the earth.
A.
gif.latex

B.
gif.latex

C.
gif.latex

D.
gif.latex


Code: 
[IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20F=G\frac{m_{1}m_{2}}{r^{2}}[/IMG]

BUT F=mg, assume m = [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20m_{1}[/IMG]

Therefore,
[IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20m_{1}g=G\frac{m_{1}m_{2}}{r^{2}}[/IMG]

[IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20m_{1}[/IMG] cancels' out

[IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20m_{e}=\frac{gr^{2}}{G}=\frac{(9.806)(6.371x10^{3})^{2}}{CONST%20 39}[/IMG]

And you will get the answer.

35. Calculate the form factor of a periodic voltage having the following values for equal time intervals changing one value to the next: 0, 5, 10, 20, 50, 60, 50, 20, 10, 5, etc.
A. 1.11
B. 1.24
C. 1.35
D. 1.41
Code: 
[IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20FormFactor=%20\frac{rms}{ave}=\frac{\sqrt{\frac{\sum%20x^{2}}{n}}}{\bar{x}}[/IMG]

Use STAT 1 and follow the formula, and you will get the answer.

36. Find the value of
gif.latex

A. 8 - 8i
B. 8 + 8i
C. 4 - 4i
D. 4 + 4i

Code: 
Ang pwede lang po sa ating calcu ay cube at square ng complex.
Pwede pong ganito: 
[IMG]http://latex.codecogs.com/gif.latex?(1+i)^{3}[/IMG][IMG]http://latex.codecogs.com/gif.latex?(1+i)^{3}[/IMG][IMG]http://latex.codecogs.com/gif.latex?(1+i)[/IMG]


Or pwede din ito:
[IMG]http://latex.codecogs.com/gif.latex?(1+i)^{3}[/IMG][IMG]http://latex.codecogs.com/gif.latex?(1+i)^{2}[/IMG][IMG]http://latex.codecogs.com/gif.latex?(1+i)^{2}[/IMG]

37. Determine the argument of the result of
gif.latex

A. -72
B. 27
C. 76.9
D. 159.4

Code: 
[IMG]http://i48.tinypic.com/qxl2c2.png[/IMG]

I-type lang po natin sa calcu yung given then press = 
Convert po natin sa polar form then booomm..Yun na..

38. I've reached the image limit. Sa next part na lang. Marami pa naman ito.

39. The resistance of a wire is 126.48 ohms at 100 degrees C and 100 ohms at 30 degrees C. Determine the temperature when the resistance is 115 ohms.
A. 65.15 degrees C
B. 69.65 degrees C
C. 71.25 degrees C
D. 75.45 degrees C

Code: 
STAT 2
X column = temp.
Y column = Resistance

---x--- | ---Y---
---100 | ---126.48
---30 | ---100

[IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20115\widehat{x}[/IMG]

40. What is the present worth of two 10,000 pesos payment at the end of the 3rd and 4th year if the annual interest is 8% compounded quarterly?
A. P 15, 169
B. P 15, 288
C. P 16, 721
D. P 17, 264

Code: 
Ang formula po talaga nito ay [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20F=P(1+\frac{i}{m})^{mt}[/IMG]

where:
F = future worth
P = present worth
i = interest rate
m = number of compounding(quarterl, semi-anually, annually etc)
t = time(years,month, days, etc)

Kung alam niyo kung paano computin sa long method, then go.. :D
Then ito po yung sa CALCU TECHNIQUE:

First kukunin natin ang P ng 3rd and 4th year. So unahin natin si 3rd year. gets?..
STAT 5 or 6
X column = mt(ito yung naka-raised sa formula)
Y column = [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20P(1+\frac{i}{m})[/IMG]

----- X ----- | ----- Y -----
----12 ----- | 10,000
----13 ----- | 1.02(10,000)

bakit po 12? kasi mt=(4)(3)
bakit po 13? kasi next year. +1 year gets?..
bakit 10,000 lang, akala ko yung formula? ginagamit lang natin yung formula on the next year.

Then get the present worth: [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%200\widehat{y}[/IMG]


Second, kukunin natin ang present worth sa 4th year. Same lang din ito sa 3rd year. Ang pinagkaiba lang yung mt..

----- X ----- | ----- Y -----
-----16----- | 10,000
-----17----- | 1.02(10,000)

Then get the present worth: [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%200\widehat{y}[/IMG]

Finally get the sum of the present worth in the 3rd year and 4th year. And you will get the answer.




:thumbsup: :thumbsup: :thumbsup:​
 
Last edited:
ang ganda ng post malaking tulong nito..dagdag ko lng sa half mo
31. A radioactive substance decreases from 10 grams to 9 grams in two hours. Find its half life.
A. 10.19 hr
B. 11.49 hr
C. 12.89 hr
D. 13. 16 hr
Click to expand...

dahil walang nakalagay nakong anung order of reaction pwd tayong mag assume na first order reaction na

at ito ang formula sa first order reaction..

t1/2=(ln 2 )/ k

An=Ao e^-kt

where:

k - rate constant value
An - amount after t
Ao - initial amount
t1/2 - half life

sa problem na ito kkunin muna natin kung value ng k then substitute natin yung nakuhang value ng k sa t1/2 value..
 
paano kung masyadong maraming equation ang makukuha ko? gaya sa mesh loop equation na ang applicable lang ay CRAMER's rule? pwede rin ba sa calcu? example 5 equations?
 
Hi! Pwede po ba paki-elaborate po ang solution for 35?

Di ko po siya ma-gets... salamat po :)
 
:help: mga sir,, patulong po sana ko,, find the value of x po? sabi ng iba quaratic formula daw po,.. but hindi ko parin masagutan.. pinagpapraktisan ko po yung nasa book,, patulong naman po mga sir/mam ksi magququiz po kami patungkol dito.. para me idea napo ako... thanks po
 

Attachments

  • valueX.bmp
    1.8 MB · Views: 7
agentedx44 said:
:help: mga sir,, patulong po sana ko,, find the value of x po? sabi ng iba quaratic formula daw po,.. but hindi ko parin masagutan.. pinagpapraktisan ko po yung nasa book,, patulong naman po mga sir/mam ksi magququiz po kami patungkol dito.. para me idea napo ako... thanks po
Click to expand...


up po,,, sa question ko. bukas na po kasi to.. sana may makatulong po,, salamat sa sasagot.. :pray:
 
brixmoon said:
ang ganda ng post malaking tulong nito..dagdag ko lng sa half mo

dahil walang nakalagay nakong anung order of reaction pwd tayong mag assume na first order reaction na

at ito ang formula sa first order reaction..

t1/2=(ln 2 )/ k

An=Ao e^-kt

where:

k - rate constant value
An - amount after t
Ao - initial amount
t1/2 - half life

sa problem na ito kkunin muna natin kung value ng k then substitute natin yung nakuhang value ng k sa t1/2 value..
Click to expand...

:thanks:

bhist said:
paano kung masyadong maraming equation ang makukuha ko? gaya sa mesh loop equation na ang applicable lang ay CRAMER's rule? pwede rin ba sa calcu? example 5 equations?
Click to expand...

Sa calcu po, hanggang 3 equation, 3 unknown lang po ang kaya.

keipidesu said:
Hi! Pwede po ba paki-elaborate po ang solution for 35?

Di ko po siya ma-gets... salamat po :)
Click to expand...

Use STAT 1 lang po then may makikita kang x column, i-input mo lang po yung mga number sa problem. May formula po tayo di ba?. sundan mo lang po. Makikita mo yun sa STAT interface. SHIFT 1(STAT)>5(VAR) at SHIFT 1(STAT)>4(SUM)
Kung anu po yung nakikita mo sa formula, pakisundan na lang po.

agentedx44 said:
:help: mga sir,, patulong po sana ko,, find the value of x po? sabi ng iba quaratic formula daw po,.. but hindi ko parin masagutan.. pinagpapraktisan ko po yung nasa book,, patulong naman po mga sir/mam ksi magququiz po kami patungkol dito.. para me idea napo ako... thanks po
Click to expand...

Ang equation mo po ay
gif.latex
kung i-eequate natin sa 0 type mo lang sa calcu then SHIFT Solve :p
:D Try mo synthetic, then by trial and error, dapat ang remainder is 0.
:unsure:
​
 
_ronald20_ said:


Ang equation mo po ay
gif.latex
kung i-eequate natin sa 0 type mo lang sa calcu then SHIFT Solve :p
:D Try mo synthetic, then by trial and error, dapat ang remainder is 0.
:unsure:
​
Click to expand...

yun,,. synthetic division nga,, nagkaidea nako... thanks
 
Last edited:
_ronald20_ said:


Use STAT 1 lang po then may makikita kang x column, i-input mo lang po yung mga number sa problem. May formula po tayo di ba?. sundan mo lang po. Makikita mo yun sa STAT interface. SHIFT 1(STAT)>5(VAR) at SHIFT 1(STAT)>4(SUM)
Kung anu po yung nakikita mo sa formula, pakisundan na lang po.


​
Click to expand...


Yey! Nakuha ko na po siya.. thank you po! :thumbsup:
 
ok ito mga kasama, malaking tulong ito. try ko din makatulong basta nakaonline ako. bc kc sa work.engineering graduate ako 1983. tnx mga tol.
 
mga sir patulong po ako.. find the value of x.,,, any method po. :pray: .thanks
 

Attachments

  • FIndX.bmp
    1.8 MB · Views: 0
agentedx44 said:
yun,,. synthetic division nga,, nagkaidea nako... thanks
Click to expand...

keipidesu said:
Yey! Nakuha ko na po siya.. thank you po! :thumbsup:
Click to expand...

:welcome:​

ngatog13 said:
ok ito mga kasama, malaking tulong ito. try ko din makatulong basta nakaonline ako. bc kc sa work.engineering graduate ako 1983. tnx mga tol.
Click to expand...
Sige po. :thanks:​
agentedx44 said:
mga sir patulong po ako.. find the value of x.,,, any method po. :pray: .thanks
Click to expand...

Bakit lahat ng equation mo walang equality?.. :think:
​
 
Hello po!

More questions pa po sana regarding Laplace, Differential and Integral Calculus and Differential Equations!

Maraming salamat po! :)
 
wow kalalabas lang ng laplace s refresher ko sa math ayus makakatulong to salamat s update sana madagdagan pa to ng bongang bonga:clap:
thx alot
 
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