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[ TUT ] MATH - CALCULATOR TECHNIQUEs

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Re: [tut] math - calculator technique

i understand you TS thanks for sharing maghihinitay kami sau ng iba pang technique para mamaster ko na calcu ko..nung nakita ko to nagets ko na polynomial sa calcu dahil sau..TS ask ko sana medyo di ko nasundan ung 3 and 5 heheheh,,nawiwili ako gamitin calcu ko ngaun:clap:
 
Re: [tut] math - calculator technique

Salamat po..I assure to you na marami pa akong ipopost..wala lang talaga akong sapat na oras..malapit ko na nga matapos yung 2nd part..:D

About sa tanong mo #3..ang root po is any number na kapag ni-substitute mo sa equation ay masasatisfy niya ang equality..So, itype mo lang po sa calculator yung equation sa left side which is
png.latex
then hit CALC function..di ba magtatanong yan kung anu value ng x mo X? try mo choice A. which is 3..kapag 0 ang sagot ibig sabihin yan ang isa sa root..
kapag sinubstitute yung 3 sa equation dapat ang sagot is 0..kagaya ng sinabi ko kailangan niyang masatisfy yung equality..

0=0

Sa number 5 same lang din..
:thumbsup:
 
Re: [tut] math - calculator technique

Salamat po..I assure to you na marami pa akong ipopost..wala lang talaga akong sapat na oras..malapit ko na nga matapos yung 2nd part..:D

About sa tanong mo #3..ang root po is any number na kapag ni-substitute mo sa equation ay masasatisfy niya ang equality..So, itype mo lang po sa calculator yung equation sa left side which is
png.latex
then hit CALC function..di ba magtatanong yan kung anu value ng x mo X? try mo choice A. which is 3..kapag 0 ang sagot ibig sabihin yan ang isa sa root..
kapag sinubstitute yung 3 sa equation dapat ang sagot is 0..kagaya ng sinabi ko kailangan niyang masatisfy yung equality..

0=0

Sa number 5 same lang din..
:thumbsup:

heheh ayus TS nagets ko na rin salamat wait ko pa lahat ng share mu BM ko na to:clap:
 
nice thread..:praise:

malaking tulong ito para sa mga nagrereview, karamihan kasi ng gumagamit ng calcu na 991 ES ay hindi nila nammaximize ang gamit ng calcu nila..:D

btw pwede ba magshare din ako dito especially sa topic na para sa EE?,
 
heheh ayus TS nagets ko na rin salamat wait ko pa lahat ng share mu BM ko na to:clap:

sure.. :approve:

nice thread..:praise:

malaking tulong ito para sa mga nagrereview, karamihan kasi ng gumagamit ng calcu na 991 ES ay hindi nila nammaximize ang gamit ng calcu nila..:D

btw pwede ba magshare din ako dito especially sa topic na para sa EE?,

:thanks: po sir bat sa appreciation..:D about po sa EE, hmhm math po ito sir, meron po lahat math ang engineering..
 
Additional Exercises - PART 2

Additional Exercises - PART 2​

11. Evaluate
png.latex

A. 9920
B. 2920
C. 9200
D. 2290

Code:
Set the calculator to computation mode: MODE>1
Input the equation as is but replace k with X..
Then press =..
And you will get the answer..

12. Find x, if
png.latex

A.
png.latex

B.
png.latex

C.
png.latex

D.
png.latex


Code:
Set calculator to computation mode..
Type the equation as is..Use the "SOLVE" function and press =..
And you will get the answer..

13. Factor
png.latex

A.
png.latex

B.
png.latex

C.
png.latex

D.
png.latex


Code:
First, type the equation and assign an arbitrary constant to substitute to x and use the CALC function..
for example X=8
The calculator will display "2197"..
Second, substitute 8 to the choices and find which one will be equal to "2197"..
Start with the first choice until you get the value of "2197"..
What we do as well in the previous examples like this is called "REVERSE ENGINEERING"..

14. Find the 15th term in the arithmetic sequence: 1,3,5,7 . . .
A. 25
B. 27
C. 29
D. 31

Code:
1. Set the calculator to STAT mode..MODE 3>2
2: A+BX is for Arithmetic Progression( A.P.)..
May makikita kayo X and Y column..And X column natin ay ang nth term while sa Y column natin ay ang A.P..
2. Input sa X column ang 1,2,3(1st term,2nd term, 3rd term)..Sa Y column naman, iinput ang 1,3,5 (kahit 3 number lang, kahit wag na yung 7)..
Which mean the 1st term of the A.P. is 1, 2nd term is 3 and 3rd term is 7..
3. After niyo mainput, press AC(don't worry hindi mabubura ang data niyo)
Sa problem ang hinahanap ay ang pang 15th term..anu ba ang value ng ika-15th term?..meaning ang hinahanap ang value sa Y column..gets?..
4. Therefore, type 15Y-hat..
Ang Y-hat ay makikita when you press SHIFT>1(STAT)>7(Reg)>5(Y-hat)..while ang X-hat ay makikita when you press SHIFT>1(STAT)>7(Reg)>4(X-hat)..take note of this dahil gagamitin natin ito in the next problems..
5. Then press =..
And you will get the answer..
Kung may tanong kayo dito at di niyo makuha pakipost na lang..

15. Find the 12th term in the geometric series: 3, 9, 27 . . .
A. 59,049
B. 177,147
C. 531,141
D. 1,594,323

Code:
1. Set the calculator to STAT mode..MODE 3>5 or MODE3>6 (it's the same for Geometric Progression, G.P.)

May makikita kayo X and Y column..And X column natin ay ang nth term while sa Y column natin ay ang G.P..
2. Input sa X column ang 1,2,3(1st term,2nd term, 3rd term)..Sa Y column naman, iinput ang 3,9,27..
Which mean the 1st term of the G.P. is 3, 2nd term is 9 and 3rd term is 27..
3. After niyo mainput, press AC(don't worry hindi mabubura ang data niyo)
Sa problem ang hinahanap ay ang pang 12th term..anu ba ang value ng ika-12th term?..meaning ang hinahanap ang value sa Y column..gets?..
4. Therefore, type 12Y-hat..
5. Then press =..
And you will get the answer..
Kung may tanong kayo dito at di niyo makuha pakipost na lang..

16. What is the sum of the first 20 terms of the sequence: 1, 3, 5, 7...
A. 361
B. 391
C. 400
D. 441

Code:
1. Set the calculator to STAT mode: MODE 3>2 (since it is A.P.)
2. In the X column, input 1,2,3..In the Y column, input 1,3,5..
3. After you input the data, press AC..Don't worry your data will not be deleted (unless you change your mode)
4. Press SHIFT>LOG(found below the ON KEY)..we will use the SUMMATION function..(SUMMATION symbol is like E)
5. Press ALPHA>)(for X)>SHIFT>1>7>5(for Y-hat)>SHIFT>)(for comma)>1>SHIFT>)(for comma)>21>)
6. You will noticed that our summation is from 1 to 21..Why 21 and not 20?..Because we start our progression in 1..If we start the progression from 0, then that's the time we use 0 to 20..

And it will be like this..walang Y-hat na symbol e..
[INDENT][IMG]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20\sum%20(X(Y-Hat),1,21)[/IMG][/INDENT]

And you will get the answer..

17. What is the sum of the infinite series: 1, -1/5, 1/25, . . .
A. 5/6
B. 4/5
C. 5/7
D. 6/7

Code:
1. Set the calculator to Computation Mode..MODE>1
Since this is an infinite series, with a common ratio of less than 1, then the sum is a finite number..(NOTE: For an infinite series with  a common ratio of greater than 1, the sum is infinite)..
2. Input the equation under SUMMATION function and get the sum from 0 to a large value, say, 50.So it will be like this..Then press =

[INDENT][IMG]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20\sum_{x=0}^{50}((-\frac{1}{5})^{x})[/IMG][/INDENT]

18. What is the sum of 6+9+12+. . .+171?
A. 4956
B. 4389
C. 5198
D. 5462

Code:
1. Set the Calculator to STAT mode..MODE3>2 (I hope you already know why MODE 3 2)
2. In the X column, input 1,2,3....In the Y column, input 6,9,12 then press AC..
3. We should get the sum but we don't know how many term does it have..So let's determine how many terms it has..Earlier in this tutorial I said X is for nth term and Y is for progression..Therefore, our code is 171X-hat..Since 171 is our last term..And the calculator will display "56"
4. now use the SUMMATION function like in number 26 but this time, its 1,56..

[INDENT][IMG]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20\sum%20(x(Y-Hat)1,56)[/IMG][/INDENT]

19. What is the 6th term of the infinite series: 1, -1/5, 1/25, ...
A. 1/3125
B. 1/15625
C. -1/3125
D. -1/15625

Code:
1. Set the calculator to Computation mode..
2. Input the general equation of the infinite series and substitute 5 to x using the CALC function to display the 6th term..And press =
[INDENT][IMG]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20\left%20(%20-\frac{1}{5}%20\right%20)^{x}[/IMG][/INDENT]

20. Rationalize the given equation:
png.latex
A. 2-5i
B. (5+10i)/6
C. 1+2i
D. (2+i)/3

Code:
1. Set the calculator to COMPLEX mode..MODE>2
2. Input the equation as it is in the calculator..(NOTE: The imaginary i is found by pressing the ENG key..
3. Then press =

And you will get the answer..




:clap::clap::clap:


 
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ok to ts.. makakatulong to sa mga Eng student....:clap:
 


sure.. :approve:



:thanks: po sir bat sa appreciation..:D about po sa EE, hmhm math po ito sir, meron po lahat math ang engineering..


ah math nga lang pala ito..:D

hindi ako nagbabasa, akala ko pati ibang topics sa engineering, hehehe
 
ah math nga lang pala ito..:D

hindi ako nagbabasa, akala ko pati ibang topics sa engineering, hehehe

ok lang po..:D

nice thread, *thumbs up* ! Marami akung maTututunan dito.

:thanks: po..

TS salamat sa part2 hehehe meron ka nyan sa MSword pwede pa attach kasi papaprint ko kagaya ng part 1 hehehe salamat adik n ako sa calcu parang PSP na ang dating sakin :clap:

wala po..tinatype ko lang ito manually..


--------------------------
pwede naman po tayo sumagot sa mga tanong ng ating ka-symb..
pwede rin po tayo magshare pero dapat about sa math..:D

:thumbsup:
 
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sayang wala akong casio na calcu ..


btw salamat na rin ..

Engr. Student .. mamaster ko na lang manual compute para kahit on the spot ung test may masagot ako :lol:
 
sayang wala akong casio na calcu ..


btw salamat na rin ..

Engr. Student .. mamaster ko na lang manual compute para kahit on the spot ung test may masagot ako :lol:

:thanks:
I hope this thread will help a lot for our members who are studying and pursuing courses with math related subjects..

:hat:
 
:thanks:
I hope this thread will help a lot for our members who are studying and pursuing courses with math related subjects..

:hat:

helpful talaga to TS .. wag lang aabusun .. baka maya malaman nila to .. araw araw na ang calcu sa math subject nila ..

tingin ko sa algebra, analytical geometry and solid measuration .. physic din pwede to


pero differential and integral calculus .. mukang malabo to magamit ..

btw salamat na din sa helpful share .. :praise:
 
Last edited:
pero differential and integral calculus .. mukang malabo to magamit ..

:D minamaliit mu ata ako ah joke..:giggle:
pwede po yan sa calculus..akong bahala sa inyo..

:dance:
 
wow... ayos to ahh... :salute: para iyo boss....maraming salamat...
 
Session 2 Part 1


SESSION 2 PART 1


1. Subtract
png.latex

A.
png.latex

B.
png.latex

C.
png.latex

D.
png.latex


Code:
Siguro naman kayang kaya niyo na ito..:D


2. During a rain, 2mm of water fell. Find how many gallons of water fell on a level 10 acre park.
A. 21,381
B. 25,381
C. 27,381
D. 30,381

Code:
Conversion only..
V=10 acre (convert acre to m^2)SHIFT>8(for CONV)>11(for acre>m^2)..It will give an answer 40468.56..
Then multiply it to .002 m(given in the problem) and it will display 80.93712 in m^3..
Convert this to Liters..1 m^3 = 1000L..And it will display 80937.12 in L..
Finally convert this to gal..Press CONV#14 L>gal(US)..
And you will get the answer in gal..

3. The function
png.latex
is discontinous at x=?
A. 2
B. -2
C. either a or b
D. neither a nor b

Code:
Pag sinabing discontinous, mageerror siya sa value na isusubstitute mo or yung tinatawag na MATH ERROR..Pag may lumalabas parin na value positive or negative or even zero, continous parin yun..dapat mageerror siya..gets?..

Set the calculator to COMP MODE..
type na equation as it is..press the CALC function and substitute the numbers in the choices and find which one will get an error..The one error is the answer..

Alternative solution..we use the TABLE function..MODE 7..
Type the equation as it is and press =
START? (your number depends on the choices..we start from the lowest which is -2..So enter -2 then press =
END? (the largest in the choices)..So enter 2 and press =
STEP? (The variation in the choices)..Important po ito..kailangan madaanan nung function yung mga choices..In this case 2 and -2..So enter 2 and press =

Kung saan may error yun na yun..

4. Find the possible factors of
png.latex
.
A. (x-2)
B. (2x-1)
C. (2x+3)
D. all of the above

Code:
Para masabing factor siya, kailangan ang y=0 pag isusubstitute natin yung root of x..
We use CALC function..Set the calculator to MODE 1..
Type the equation as it is and press CALC..Get the root of the choices and substitute..
X? enter 2 if y=0, then possible root siya..Try the next one..
X? enter 1/2, if y=0, then possible root siya..Try the last one..
X? enter -3/2 if y=0, then possible root siya..

Therefore you know the answer..

5. Determine the area of the triangle bounded by the straight lines x+2y-7=0, 3x-4y-1=0, and 2x-y+6=0..
A. 10 sq.units
B. 15 sq.units
C. 20 sq.units
D. 25 sq.units

Code:
First get the point of intersection..use the EQN function..MODE 5>1
For the first two equation, type:
1 2 7
3 -4 1
then press = =..Therefore the point of intersection of this is x=3, and y=2..
Then try the next equation..
3 -4 1
2 -1 -6
Then press = =......x=-5, and y=-4
try the last combination of equation..
1 2 7
2 -1 -6
Then press = =......x=-1, and y=4
Then we use the determinant function to get the area of the triangle..
Set the calculator to MATRIX..MODE 6 and press AC..
What important in this is kailangan natin madaan yung DIM or dimension ng matrix..So press SHIFT>4>1>1>1 and enter
3 2 1
-5 -4 1
-1 4 1
then press AC..
To get the determinant press SHIFT>7(det)>SHIFT>4>3(since we enter our data in MatA..Then press =..
Remember the area of a triangle given the vertices is 0.5 times the determinant..Therefore multiply it to 0.5 and get its Abs value..
Then you will get the final answer..

6. Find the center of the circle that is circumscribed about the triangle whose vertices are (-3,1), (3,1) and (5,3)
A. (-3,9)
B. (3,-9)
C. (-3,-9)
D. (3,9)

Code:
Substitute x and y in the general equation of circle.. [IMG]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20x^{2}+y^{2}+Dx+Ey+F=0[/IMG]
In the first point you will get the equation -3D-E+F=-10
The second point will give you 3D+E+F=-10
The third point will give you 5D+3E+F=-34..

Therefore we have 3 equations, 3 unknown..
Use the EQN 2 and enter
-3 -1 1 -10
3 1 1 -10
5 3 1 -34
And you will get D=6, E=-18, and F=-10
And write it in the general form..
[IMG]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20x^{2}+y^{2}+6x-18y-10=0[/IMG]

Ito ang shortcut para makuha ang center..
CENTER OF CIRCLE, ELLIPSE or PARABOLA:
(h)
[IMG]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20x=-\frac{Cx}{2Cx^{2}}[/IMG]

(k)
[IMG]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20y=-\frac{Cy}{2Cy^{2}}[/IMG]

Therefore our center (h,k) is at (-3,9)..

7. Find the value of y of the parabola whose axis is vertical and passes through (-1,0), (5,0), (1,8) and (4,y)
A. -5
B. 5
C. -6
D. 6

Code:
We use STAT 3( for parabola) in this case..
In the x column enter -1,5 and 1..
In the y column enter 0,0, and 8 then press AC

Find the value of y when x = 4..
therefore 4(y-hat) or [IMG]http://latex.codecogs.com/png.latex?\small%20\fn_cm%204\widehat{y}[/IMG]

And you will get the answer..

8. Find the sum of an A.P.: 2,5,8..............where n=25..
A. 900
B. 925
C. 950
D. 975

Code:
Use STAT 2(for A.P.)
In the x column enter 1,2
In the y column enter 2,5 then press AC..
Use the SUMMATION FUNCTION..

[INDENT][IMG]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20\sum%20(x\widehat{y},1,25)[/IMG][/INDENT]

And you will get the answer..

9. Find the sum of a G.P.: 2,3,4.5,.................where n=10.
A. 226.66
B. 235.42
C. 242.52
D. 251.84

Code:
Same method with #9 BUT use STAT 6(for G.P.)
Then use the SUMMATION function to get the sum..
And you will get the answer..

10. In how many ways can a picture be painted by using three(3) or more of the seven(7) different colors?.
A. 80
B. 99
C. 105
D. 120

Code:
Set the calculator to COMP MODE..
We use the COMBINATION function..It will be found by pressing SHIFT > ÷ ( nCr )
And type the equation just like this:

[INDENT][IMG]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20_{7}\textrm{C}_{3}+_{7}\textrm{C}_{4}+_{7}\textrm{C}_{5}+_{7}\textrm{C}_{6}+_{7}\textrm{C}_{7}[/IMG][/INDENT]

And you will get the answer..







 
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