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[ TUT ] MATH - CALCULATOR TECHNIQUEs

Nakatulong ba?

  • Oo, malaking tulong..Natututo ako dito..More pa TS

    Votes: 194 97.0%

  • Hindi, alam ko na yan lahat

    Votes: 6 3.0%
  • Total voters
    200
This is so helpful... I am a compsci grad mag tetake ako ng let this aug 17 major in math... thanks thanks thanks a lot..:clap:...
 
thank you po....:clap::clap::clap::clap:

may mga book na calculator techniques din po b?
...yung nka pdf n din po sana....
 
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Last edited:
Re: [tut] math - calculator technique

long live po... thanks for sharing
 
maraming salamat dito, TS! mas mapapabilis pag-check ko. :D
 
Sir, may tanong po ako. Paano po malaman ang complex root ng equation na greater than 3 ang highest exponent?
Parang ganito po X^4 + 8X^2 + 16 = y
Ang roots po ay +-2i, +-2i
Posible po ba yun sa calculator? Salamat ts.
 
ifyoseekayou said:
Sir, may tanong po ako. Paano po malaman ang complex root ng equation na greater than 3 ang highest exponent?
Parang ganito po X^4 + 8X^2 + 16 = y
Ang roots po ay +-2i, +-2i
Posible po ba yun sa calculator? Salamat ts.
Click to expand...

Sa pagkakaalam ko lang po, hindi pa po supported ng mga latest calculator ang 3 roots.
 
Re: [tut] math - calculator technique

Thank you, TS! Pwede pala mahanap GS sa DE gamit calcu. Haha :D
 
Re: [tut] math - calculator technique

Meron ba kayo para sa fourier transform? thanks.
 
Re: [tut] math - calculator technique

salamat dito ts! laking tulong. ece rin kukunin for college. haha! :thanks:
 
Re: [tut] math - calculator technique

sino po marunong magsolve ng Peg Test at Stadia Method sa surveying dito may tanon sana ako, or any link kung pano magsolve nung nabanggit TIA :D
 
Re: [tut] math - calculator technique

thanks ts.mahirap pa naman gamitin mga scientific calcus
 
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Re: Session 2 Part 2

SiRhOSEven said:
SESSION 2 PART 2
Starting in this Part, di ko na iisa-isahin kung anu pipindutin niyo para madali tayo..Kung may tanong kayo at di niyo makuha, pakipost na lang..​


11. Find the decimal equivalent of http://latex.codecogs.com/png.latex?\small \fn_cm 101,110,001,111,101_{2}
A. 32677
B. 36277
C. 23677
D. 26377

Code: 
Convert niyo lang sa decimal..
MODE 4..Set to BIN then type the number..
Press DEC and you got the answer..

[B]Additional TIP:[/B]
Kung hindi na kasya sa calculator at sobrang haba ng BIN mo, iconvert mo muna sa OCT..
101=5
110=6
001=1
111=7
101=5

Set to OCT and type the OCT equivalent, 56175
And press DEC and you got the answer..

12. Find the hexadecimal equivalent of http://latex.codecogs.com/png.latex?\small \fn_cm 1234_{8} x http://latex.codecogs.com/png.latex?\small \fn_cm 5678_{10}

A. http://latex.codecogs.com/png.latex?\small \fn_cm E1A120_{16}
B. http://latex.codecogs.com/png.latex?\small \fn_cm EA1120_{16}
C. http://latex.codecogs.com/png.latex?\small \fn_cm 93E008_{16}
D. http://latex.codecogs.com/png.latex?\small \fn_cm 39E008_{16}

Code: 
Type niyo lang sa calcu..Wag kalimutan base 8 and base 10 yan..
Press HEX for the final answer..

13. Evaluate A x B.
http://latex.codecogs.com/png.latex...& 6 & 0\\ 4 & 2 & 7\\ 0 & 5 & 3 \end{vmatrix}
http://latex.codecogs.com/png.latex... -4\\ -3 & 6 & -7\\ 4 & -4 & -6 \end{vmatrix}


A. http://latex.codecogs.com/png.latex... 26 & -24 & -72\\ -3 & 18 & -53 \end{vmatrix}
B. http://latex.codecogs.com/png.latex... -3 & 18 & -53\\ 26 & -24 & -72 \end{vmatrix}
C. http://latex.codecogs.com/png.latex...-17 & 34 & -46\\ 26 & -24 & -72 \end{vmatrix}
D. http://latex.codecogs.com/png.latex...26 & -24 & -72\\ -17 & 34 & -46 \end{vmatrix}

Code: 
MODE 6>AC.....Tandaan daanan lagi si DIM..
SHIFT>4>1
Itype ang matrix and that's it..
You got the answer..

[B]Additional TIP:[/B]
If A/B, DON'T use divide, instead use the reverse function..And it will be like this
[url]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20MatA%20x%20MatB^{-1}[/url]

14. Find dy/dx if http://latex.codecogs.com/png.latex?\small \fn_cm y=t^{3}-2t+1 and http://latex.codecogs.com/png.latex?\small \fn_cm t=cos(x-\frac{\Pi }{6}) when http://latex.codecogs.com/png.latex?\small \fn_cm x=\frac{\Pi }{2}

A. 0.433
B. 0.866
C. 1.083
D. 1.732

Code: 
Pag Trigonometric/Inverse, i-set ang calcu sa RADIAN MODE..
I-type sa calcu like this..
[url]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20\frac{d}{dx}((cos(x-\frac{\Pi%20}{6}))^{3}-2(cos(x-\frac{\Pi%20}{6}))+1)_{x=\frac{\Pi}{2}}[/url]

Yung [url]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20\Pi[/url] po natin diyan, pi po yun..

15. If y = 4tanh x + sinh 2x, what is the slope of the curve when x = 2?
A. -54.9
B. -28.2
C. 54.9
D. 28.2

Code: 
TANDAAN:
Slope = first derivative = [url]http://latex.codecogs.com/png.latex?\small%20\fn_cm%20y^{'}[/url]

To get the slope, simply get the first derivative of the equation..
And you will get the answer..

16. Find the slope of the equation http://latex.codecogs.com/png.latex?\small \fn_cm r=sin^{2}\Theta when http://latex.codecogs.com/png.latex?\small \fn_cm \Theta=\frac{\Pi }{3}
A. 5.2
B. -5.2
C. 4.2
D. -4.2

Code: 
[url]http://i2.lulzimg.com/8f960b7c9f.png[/url]
Gagawa tayo ng equation from the figure, since may given tayo na r and theta..Then we must come up with [url]http://latex.codecogs.com/gif.latex?\frac{dy/d\theta}{dx/d\theta}[/url]

Using Pythagorean theorem:
[url]http://latex.codecogs.com/gif.latex?y=rsin\theta[/url]
And derive with respect to theta..
Substituting the given and using the d/dx function of the calcu, it will be like this:
[url]http://latex.codecogs.com/gif.latex?\frac{d}{dx}((sin%20x)^{3})_{x=\frac{\Pi%20}{3}}[/url]


Next we must get [url]http://latex.codecogs.com/gif.latex?dx/d\theta[/url]
From the figure, we have [url]http://latex.codecogs.com/gif.latex?cos\theta%20=\frac{x}{r}[/url]
and equating it to x, we have:
[url]http://latex.codecogs.com/gif.latex?x=rcos\theta[/url]
Substituting the given and getting the derivative of x with respect to theta, we have:
[url]http://latex.codecogs.com/gif.latex?\frac{d}{dx}((sinx)^{2}(cos%20x))_{x=\frac{\Pi%20}{3}}[/url]


Dividing the results and you got the answer..

17. Find the equation of the nomal line of the curve http://latex.codecogs.com/gif.latex?y=3x^{2}-2x+1 at (1,2)
A. 4x-y=2
B. 4x-y=-2
C. x+4y=9
D. x+4y=-9

Code: 
When you are getting the slope of the line using the first derivative, what you are getting is the slope of the tangent line..To get the slope of the Normal Line, you get the negative reciprocal of this..
So, get the first derivate(Tangent slope) of the given equation with x=1(given in the problem)
[url]http://latex.codecogs.com/gif.latex?\frac{d}{dx}(3x^{2}-2x+1)_{x=1}[/url]

And getting the negative reciprocal of this we have -1/4..
Then get the equation using STAT 2..
[url]http://i2.lulzimg.com/318dce074d.png[/url]

And press AC..Get A and B..
SHIFT>1>7> and SHIFT>1>7>2

Remember, in the calculator, the equation of STAT 2 is y=a+bx..
Substitute a and b in the equation and you will get the answer..

18. The charge in coulombs that passes through a wire after t seconds is given by the function. http://latex.codecogs.com/gif.latex?Q(t)=t^{3}-2t^{2}+5t+2
Determine the current at the end of 2 seconds..
A. 6 A
B. 8 A
C. 9 A
D. 10 A

Code: 
Simple get the first derivative of this with x=2 (2 seconds) and you will get the answer..

19. A 1800-gallon tank of water drains from the bottm in 30 min. According to Torricelli's law, the volume of water remaining in the tant after t minutes is
http://latex.codecogs.com/gif.latex?V=1800(1-\frac{t}{30})^{2} where http://latex.codecogs.com/gif.latex?0\leq t\leq 30
How fast is the water draining from the tant after 20 minutes?
A. -40 gpm
B. -30 gpm
C. -20 gpm
D. -10 gpm

Code: 
Simply get the derivative of the equation with x=20 (20 minutes)..
And you will get the answer in gpm..

20. Find the value of x when the function y=lnx/x is at maximum value.
A. 0
B. e
C. 1
D. 1/e

Code: 
For maxima/minima, the first derivative should be equal to 0..
Try or test all the choices using CALC function if dy/dx=0 with x = x to use CALC function while getting the derivative..
[url]http://latex.codecogs.com/gif.latex?\frac{d}{dx}(\frac{ln%20x}{x})_{x=x}[/url]

and press CALC

x? 0
x? e
x? 1
x? 1/e

Kung anu sa choices ang nag equal to 0, yun ang sagot..
Click to expand...


hindi ko poh mkuha ung #12...!! hindi ko po alam kung paano eh base 8 sa calcu.. pa help poh
 
Re: Session 2 Part 2

salamat dito ts :salute:
engineer na ako.. september 2014 passer REE
isa ito sa mga naging reviewer ko during my review sa baguio city, ACERS review center
 
Re: Session 2 Part 2

TS Sobra laki ng tulong ng thread mo. Reviewer ako ngayon for REE exams. Ok lang ba ishare ko yung mga examples mo sa iba kong kaklase? :salute:
 
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