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Re: Session 2 Part 4
thanks, malaking tulong talaga to sa mga di nagenroll ng calcu tech.
SESSION 2 PART 4
31. A radioactive substance decreases from 10 grams to 9 grams in two hours. Find its half life.
A. 10.19 hr
B. 11.49 hr
C. 12.89 hr
D. 13. 16 hr
Code:Dahil sa ito ay radioactive, nagiincrease ito exponentially. Which means kung exponentially ito, gagamitin natin ang STAT 5.. Ang x column natin ay ang time(hr) and y column natin ay quantity.. X-----|-----Y 0-----|-----10 2-----|-----9 since time in its half life ang hinahanap, press AC then find [IMG]http://latex.codecogs.com/gif.latex?5\hat{x}[/IMG]
32. A thermometer readingis brought into a room where the temperature is; 1 min later, the thermometer reading is. Find the temperature equation as a function of time.
A.
B.
C.
D.
Code:Pag temperature ang pinaguusapan use STAT 5. Sa x column natin is the time(min) and in y column it's either "Ts-T" or "T-Ts" (temperature). It depends kung sino malaki kung si T or si Ts.. T = Object temperature Ts = surrounding/environment temperature gets?. Let's proceed.. Since malaki ang Ts natin which is [IMG]http://latex.codecogs.com/gif.latex?70^{\circ}F[/IMG], therefore ang gagamitin natin ay Ts-T. Gets?.. X-----|-----Y(Ts-T) 0-----|-----(70-18) 1-----|-----(70-31) After natin ma-input ang data, press AC. Since ang kinukuha natin dito ay equation, therefore kukunin natin ang value ng A and B. I hope and assume na you know it already kung paano at saan ito kukunin since naturo ko na ito sa naunang session/part.. After makuha ang A and B, alam natin na ang equation sa STAT 5 ay [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20y=Ae^{bx}[/IMG] I-substitute ang A and B, x=t and y=Ts-T since yun ang ginamit natin(y=70-T)
33. How fast does light travel in glass of refractive index 1.5?
A.
B.
C.
D.
Code:Refractive index formula [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20n=\frac{c(vacuum)}{v(medium)}[/IMG] [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%201.5=\frac{3x10^{8}}{v}[/IMG]
34. At the surface of the earth,. Assume the earth to be a sphere of radius 6,371 km, compute the mass of the earth.
A.
B.
C.
D.
Code:[IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20F=G\frac{m_{1}m_{2}}{r^{2}}[/IMG] BUT F=mg, assume m = [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20m_{1}[/IMG] Therefore, [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20m_{1}g=G\frac{m_{1}m_{2}}{r^{2}}[/IMG] [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20m_{1}[/IMG] cancels' out [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20m_{e}=\frac{gr^{2}}{G}=\frac{(9.806)(6.371x10^{3})^{2}}{CONST%20 39}[/IMG] And you will get the answer.
35. Calculate the form factor of a periodic voltage having the following values for equal time intervals changing one value to the next: 0, 5, 10, 20, 50, 60, 50, 20, 10, 5, etc.
A. 1.11
B. 1.24
C. 1.35
D. 1.41
Code:[IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20FormFactor=%20\frac{rms}{ave}=\frac{\sqrt{\frac{\sum%20x^{2}}{n}}}{\bar{x}}[/IMG] Use STAT 1 and follow the formula, and you will get the answer.
36. Find the value of
A. 8 - 8i
B. 8 + 8i
C. 4 - 4i
D. 4 + 4i
Code:Ang pwede lang po sa ating calcu ay cube at square ng complex. Pwede pong ganito: [IMG]http://latex.codecogs.com/gif.latex?(1+i)^{3}[/IMG][IMG]http://latex.codecogs.com/gif.latex?(1+i)^{3}[/IMG][IMG]http://latex.codecogs.com/gif.latex?(1+i)[/IMG] Or pwede din ito: [IMG]http://latex.codecogs.com/gif.latex?(1+i)^{3}[/IMG][IMG]http://latex.codecogs.com/gif.latex?(1+i)^{2}[/IMG][IMG]http://latex.codecogs.com/gif.latex?(1+i)^{2}[/IMG]
37. Determine the argument of the result of
A. -72
B. 27
C. 76.9
D. 159.4
Code:[IMG]http://i48.tinypic.com/qxl2c2.png[/IMG] I-type lang po natin sa calcu yung given then press = Convert po natin sa polar form then booomm..Yun na..
38. I've reached the image limit. Sa next part na lang. Marami pa naman ito.
39. The resistance of a wire is 126.48 ohms at 100 degrees C and 100 ohms at 30 degrees C. Determine the temperature when the resistance is 115 ohms.
A. 65.15 degrees C
B. 69.65 degrees C
C. 71.25 degrees C
D. 75.45 degrees C
Code:STAT 2 X column = temp. Y column = Resistance ---x--- | ---Y--- ---100 | ---126.48 ---30 | ---100 [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20115\widehat{x}[/IMG]
40. What is the present worth of two 10,000 pesos payment at the end of the 3rd and 4th year if the annual interest is 8% compounded quarterly?
A. P 15, 169
B. P 15, 288
C. P 16, 721
D. P 17, 264
Code:Ang formula po talaga nito ay [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20F=P(1+\frac{i}{m})^{mt}[/IMG] where: F = future worth P = present worth i = interest rate m = number of compounding(quarterl, semi-anually, annually etc) t = time(years,month, days, etc) Kung alam niyo kung paano computin sa long method, then go.. :D Then ito po yung sa CALCU TECHNIQUE: First kukunin natin ang P ng 3rd and 4th year. So unahin natin si 3rd year. gets?.. STAT 5 or 6 X column = mt(ito yung naka-raised sa formula) Y column = [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%20P(1+\frac{i}{m})[/IMG] ----- X ----- | ----- Y ----- ----12 ----- | 10,000 ----13 ----- | 1.02(10,000) bakit po 12? kasi mt=(4)(3) bakit po 13? kasi next year. +1 year gets?.. bakit 10,000 lang, akala ko yung formula? ginagamit lang natin yung formula on the next year. Then get the present worth: [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%200\widehat{y}[/IMG] Second, kukunin natin ang present worth sa 4th year. Same lang din ito sa 3rd year. Ang pinagkaiba lang yung mt.. ----- X ----- | ----- Y ----- -----16----- | 10,000 -----17----- | 1.02(10,000) Then get the present worth: [IMG]http://latex.codecogs.com/gif.latex?\dpi{100}%200\widehat{y}[/IMG] Finally get the sum of the present worth in the 3rd year and 4th year. And you will get the answer.
thanks, malaking tulong talaga to sa mga di nagenroll ng calcu tech.